(2e^2-4e-3)+(7e^2-e+6)=0

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Solution for (2e^2-4e-3)+(7e^2-e+6)=0 equation: 



(2e^2-4e-3)+(7e^2-e+6)=0

We get rid of parentheses

2e^2+7e^2-4e-e-3+6=0

We add all the numbers together, and all the variables

9e^2-5e+3=0

a = 9; b = -5; c = +3;
Δ = b2-4ac
Δ = -52-4·9·3
Δ = -83
Delta is less than zero, so there is no solution for the equation

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